What is the limit as x approaches 0 of e^{(ln(x))/x} ?

The limit as x approaches 0 of e^{(ln(x))/x} is Does not exist

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limit as x approaches 0 of e^{(ln(x))/x}

x \to 0 lim (e^{\frac{l n ( x )}{x}})

Does not exist

Solution steps

x \to 0 lim (e^{\frac{l n ( x )}{x}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (e^{\frac{l n ( x )}{x}}) = 0

x \to 0 - lim (e^{\frac{l n ( x )}{x}}) =

Does not exist

= Does not exist

x \to \frac{π}{2} lim (- tan (x))

x \to 0 lim (\frac{1}{3 ^{\frac{1}{x}} + 1})

x \to 1 lim (5 - x^{2})

x \to π lim (π - x)

x \to 0 + lim ((- 8 ln (x))^{x})

What is the limit as x approaches 0 of e^{(ln(x))/x} ?
The limit as x approaches 0 of e^{(ln(x))/x} is Does not exist