What is the solution for (dy)/(dx)=xy^4-y ?

The solution for (dy)/(dx)=xy^4-y is y=\sqrt[3]{3/(3x+1+3c_{1)e^{3x}}}

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(dy)/(dx)=xy^4-y

\frac{d y}{d x} = x y^{4} - y

Solution steps

\frac{d y}{d x} = x y^{4} - y

Solve Bernoulli ODE:

x \to 1 - f lim (x)

\frac{d}{d x} ((1 + 8 x^{2}) (x - x^{2}))

y = - x^{3}, x = - 2, x = 2, y = 0

x \to - 8 lim (\frac{12 x}{8 + x})

\frac{d}{d x} (2 + e^{- x^{3}})

What is the solution for (dy)/(dx)=xy^4-y ?
The solution for (dy)/(dx)=xy^4-y is y=\sqrt[3]{3/(3x+1+3c_{1)e^{3x}}}