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Popular >

derivative of (1+8x^2(x-x^2))

Solution

\frac{d}{d x} ((1 + 8 x^{2}) (x - x^{2}))

Solution

- 32 x^{3} + 24 x^{2} - 2 x + 1

Solution steps

\frac{d}{d x} ((1 + 8 x^{2}) (x - x^{2}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 1 + 8 x^{2}, g = x - x^{2}

= \frac{d}{d x} (1 + 8 x^{2}) (x - x^{2}) + \frac{d}{d x} (x - x^{2}) (1 + 8 x^{2})

\frac{d}{d x} (1 + 8 x^{2}) = 16 x

\frac{d}{d x} (x - x^{2}) = 1 - 2 x

= 16 x (x - x^{2}) + (1 - 2 x) (1 + 8 x^{2})

Simplify

16 x (x - x^{2}) + (1 - 2 x) (1 + 8 x^{2}) : - 32 x^{3} + 24 x^{2} - 2 x + 1

= - 32 x^{3} + 24 x^{2} - 2 x + 1

Popular Examples

area y=-x^3,x=-2,x=2,y=0 area

y = - x^{3}, x = - 2, x = 2, y = 0

limit as x approaches-8 of (12x)/(8+x)

x \to - 8 lim (\frac{12 x}{8 + x})

derivative of 2+e^{-x^3}

\frac{d}{d x} (2 + e^{- x^{3}})

tangent of f(x)= x/(2x+3),\at x=-1 tangent of

f (x) = \frac{x}{2 x + 3}, at x = - 1

(\partial)/(\partial x)(3x)

\frac{\partial}{\partial x} (3 x)

Frequently Asked Questions (FAQ)

What is the derivative of (1+8x^2(x-x^2)) ?
The derivative of (1+8x^2(x-x^2)) is -32x^3+24x^2-2x+1
What is the first derivative of (1+8x^2(x-x^2)) ?
The first derivative of (1+8x^2(x-x^2)) is -32x^3+24x^2-2x+1