What is the tangent of f(x)= x/(2x+3),\at x=-1 ?

The tangent of f(x)= x/(2x+3),\at x=-1 is y=3x+2

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tangent of f(x)= x/(2x+3),\at x=-1

tangent of

f (x) = \frac{x}{2 x + 3}, at x = - 1

y = 3 x + 2

Solution steps

Find the tangent point:

(- 1, - 1)

Find the slope of

f (x) = \frac{x}{2 x + 3} : \frac{df ( x )}{d x} = \frac{3}{( 2 x + 3 ) ^{2}}

Compute the slope of

f (x) = \frac{x}{2 x + 3}

x = - 1 : m = 3

Find the line with slope m=

3

and passing through

(- 1, - 1) : y = 3 x + 2

y = 3 x + 2

\frac{\partial}{\partial x} (3 x)

\int \frac{1 + tan ( x )}{x + ln ∣ sec ( x ) ∣} d x

\frac{d}{d x} (x 4 + 3 x^{3})

\frac{d}{d x} (3 sin (5 x))

x \to \infty lim ((\frac{1}{3})^{x + 2} + 4)

What is the tangent of f(x)= x/(2x+3),\at x=-1 ?
The tangent of f(x)= x/(2x+3),\at x=-1 is y=3x+2