What is the derivative of 3sin(5x) ?

The derivative of 3sin(5x) is 15cos(5x)

What is the first derivative of 3sin(5x) ?

The first derivative of 3sin(5x) is 15cos(5x)

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\frac{d}{d x} (3 sin (5 x))

15 cos (5 x)

Solution steps

\frac{d}{d x} (3 sin (5 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (sin (5 x))

Apply the chain rule:

cos (5 x) \frac{d}{d x} (5 x)

= cos (5 x) \frac{d}{d x} (5 x)

\frac{d}{d x} (5 x) = 5

= 3 cos (5 x) \cdot 5

Simplify

= 15 cos (5 x)

x \to \infty lim ((\frac{1}{3})^{x + 2} + 4)

\frac{4 s}{( 4 s ^{2} + 1 )}

\frac{d}{d x} (3 + cos (x))

n = 0 \sum \infty e^{- n} + 1

\int \frac{x}{4 + x ^{2}} d x

What is the derivative of 3sin(5x) ?
The derivative of 3sin(5x) is 15cos(5x)
What is the first derivative of 3sin(5x) ?
The first derivative of 3sin(5x) is 15cos(5x)