What is the limit as x approaches 0+of e^{1/(x^2)} ?

The limit as x approaches 0+of e^{1/(x^2)} is infinity

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limit as x approaches 0+of e^{1/(x^2)}

x \to 0 + lim (e^{\frac{1}{x ^{2}}})

\infty

Solution steps

x \to 0 + lim (e^{\frac{1}{x ^{2}}})

Apply the Limit Chain Rule:

\infty

= \infty

x \to - 1 lim (2 x^{3} - 3 x)

x \to 0 lim (\frac{1 + ln ( x )}{x})

x \to - 6 - lim (\frac{2 x}{6 + x})

u \to - 2 lim (\frac{u + 2}{u ^{3} + 8})

t \to 0 + lim ((sin (t))^{t})

What is the limit as x approaches 0+of e^{1/(x^2)} ?
The limit as x approaches 0+of e^{1/(x^2)} is infinity