What is the limit as u approaches-2 of (u+2)/(u^3+8) ?

The limit as u approaches-2 of (u+2)/(u^3+8) is 1/12

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limit as u approaches-2 of (u+2)/(u^3+8)

u \to - 2 lim (\frac{u + 2}{u ^{3} + 8})

\frac{1}{12}

Decimal Notation

0.08333 \dots

Solution steps

u \to - 2 lim (\frac{u + 2}{u ^{3} + 8})

Simplify

\frac{u + 2}{u ^{3} + 8} : \frac{1}{u ^{2} - 2 u + 4}

= u \to - 2 lim (\frac{1}{u ^{2} - 2 u + 4})

Plug in the value

u = - 2

= \frac{1}{( - 2 ) ^{2} - 2 ( - 2 ) + 4}

Simplify

\frac{1}{( - 2 ) ^{2} - 2 ( - 2 ) + 4} : \frac{1}{12}

= \frac{1}{12}

t \to 0 + lim ((sin (t))^{t})

x \to 0 lim (+ (cos (2 x)) \frac{1}{x})

x \to 0 lim (\frac{1}{x} ln (x))

x \to 0 lim (\frac{( sin ( 5 x ) )}{sin ( 4 x )})

x \to 6 - lim (\frac{x - [ x ]}{x - 6})

What is the limit as u approaches-2 of (u+2)/(u^3+8) ?
The limit as u approaches-2 of (u+2)/(u^3+8) is 1/12