What is (\partial)/(\partial x)(-sin(2x)) ?

The answer to (\partial)/(\partial x)(-sin(2x)) is -cos(2x)*2

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(\partial)/(\partial x)(-sin(2x))

\frac{\partial}{\partial x} (- sin (2 x))

- cos (2 x) \cdot 2

Solution steps

\frac{\partial}{\partial x} (- sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{\partial}{\partial x} (2 x)

= cos (2 x) \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= - cos (2 x) \cdot 2

y = \frac{( x ^{2} + 3 )}{2 x}

\frac{d}{d x} (ln (12 cos^{2} (x)))

x \to 0 lim (x lo g_{e} (x))

\frac{d}{d x} ((1 + \frac{2}{x})^{x})

\frac{d}{d x} (\frac{e ^{3 x}}{e ^{3 x} + 2})

What is (\partial)/(\partial x)(-sin(2x)) ?
The answer to (\partial)/(\partial x)(-sin(2x)) is -cos(2x)*2