What is the derivative of y=((x^2+3))/(2x) ?

The derivative of y=((x^2+3))/(2x) is (x^2-3)/(2x^2)

What is the first derivative of y=((x^2+3))/(2x) ?

The first derivative of y=((x^2+3))/(2x) is (x^2-3)/(2x^2)

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derivative of

y = \frac{( x ^{2} + 3 )}{2 x}

\frac{x ^{2} - 3}{2 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} + 3}{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{x ^{2} + 3}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{2} \cdot \frac{\frac{d}{d x} ( x ^{2} + 3 ) x - \frac{d x}{d x} ( x ^{2} + 3 )}{x ^{2}}

\frac{d}{d x} (x^{2} + 3) = 2 x

\frac{d x}{d x} = 1

= \frac{1}{2} \cdot \frac{2 xx - 1 \cdot ( x ^{2} + 3 )}{x ^{2}}

Simplify

\frac{1}{2} \cdot \frac{2 xx - 1 \cdot ( x ^{2} + 3 )}{x ^{2}} : \frac{x ^{2} - 3}{2 x ^{2}}

= \frac{x ^{2} - 3}{2 x ^{2}}

\frac{d}{d x} (ln (12 cos^{2} (x)))

x \to 0 lim (x lo g_{e} (x))

\frac{d}{d x} ((1 + \frac{2}{x})^{x})

\frac{d}{d x} (\frac{e ^{3 x}}{e ^{3 x} + 2})

\frac{d}{d x} (\frac{- 3}{x ^{2}})

What is the derivative of y=((x^2+3))/(2x) ?
The derivative of y=((x^2+3))/(2x) is (x^2-3)/(2x^2)
What is the first derivative of y=((x^2+3))/(2x) ?
The first derivative of y=((x^2+3))/(2x) is (x^2-3)/(2x^2)