en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=12t^2e^{-y}

Solution

y^{^{'}} = 12 t^{2} e^{- y}

Solution

y = ln (4 t^{3} + c_{1})

Solution steps

y^{'} (t) = 12 t^{2} e^{- y}

Solve separable ODE:

y = ln (4 t^{3} + c_{1})

y = ln (4 t^{3} + c_{1})

Popular Examples

integral of (x^2)/(sqrt(x^6+9))

\int \frac{x ^{2}}{x ^{6} + 9} d x

integral of (4x)/((x^2+1)(x^2+2x+3))

\int \frac{4 x}{( x ^{2} + 1 ) ( x ^{2} + 2 x + 3 )} d x

integral from 0 to 10 of 20te^{-0.6t}

\int_{0}^{10} 20 t e^{- 0.6 t} d t

integral of (x+3)/((x+1)(x+2))

\int \frac{x + 3}{( x + 1 ) ( x + 2 )} d x

area-X^3+X,X=-1,Y=-1/2 area

- X^{3} + X, X = - 1, Y = - \frac{1}{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'=12t^2e^{-y} ?
The solution for y^'=12t^2e^{-y} is y=ln(4t^3+c_{1})