What is area-X^3+X,X=-1,Y=-1/2 ?

The answer to area-X^3+X,X=-1,Y=-1/2 is 1.05171…

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area-X^3+X,X=-1,Y=-1/2

area

- X^{3} + X, X = - 1, Y = - \frac{1}{2}

1.05171 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1.19148 \dots} \frac{1}{2} - X^{3} + X d X

Solve

\int_{- 1}^{1.19148 \dots} \frac{1}{2} - X^{3} + X d X : 1.05171 \dots

The area is:

= 1.05171 \dots

\frac{d}{d x} (arccos (\frac{x}{2}))

f (- 1) = 4 x^{2} + 4 x - 3

f (x) = (\frac{x}{x + 1})^{2}

\frac{\partial}{\partial y} (e^{x} (1 - cos (y)))

\frac{4}{s - 2}

What is area-X^3+X,X=-1,Y=-1/2 ?
The answer to area-X^3+X,X=-1,Y=-1/2 is 1.05171…