What is the derivative of f(-1)=4x^2+4x-3 ?

The derivative of f(-1)=4x^2+4x-3 is 8x+4

What is the first derivative of f(-1)=4x^2+4x-3 ?

The first derivative of f(-1)=4x^2+4x-3 is 8x+4

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derivative of

f (- 1) = 4 x^{2} + 4 x - 3

8 x + 4

Solution steps

\frac{d}{d x} (4 x^{2} + 4 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (3)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3) = 0

= 8 x + 4 - 0

Simplify

= 8 x + 4

f (x) = (\frac{x}{x + 1})^{2}

\frac{\partial}{\partial y} (e^{x} (1 - cos (y)))

\frac{4}{s - 2}

y^{^{'}} = \frac{( x ^{2} + 3 y ^{2} )}{2 x y}

x \to - 2 lim (2 x + 3)

What is the derivative of f(-1)=4x^2+4x-3 ?
The derivative of f(-1)=4x^2+4x-3 is 8x+4
What is the first derivative of f(-1)=4x^2+4x-3 ?
The first derivative of f(-1)=4x^2+4x-3 is 8x+4