What is inverse oflaplace 4/(s-2) ?

The answer to inverse oflaplace 4/(s-2) is 4e^{2t}

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inverse oflaplace 4/(s-2)

inverse laplace

\frac{4}{s - 2}

4 e^{2 t}

Solution steps

L^{- 1} {\frac{4}{s - 2}}

= L^{- 1} {4 \cdot \frac{1}{s - 2}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 4 L^{- 1} {\frac{1}{s - 2}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - 2}} = e^{2 t}

= 4 e^{2 t}

y^{^{'}} = \frac{( x ^{2} + 3 y ^{2} )}{2 x y}

x \to - 2 lim (2 x + 3)

(2 t^{2} - 1)^{3}

x \to 3 lim (x - 13)

What is inverse oflaplace 4/(s-2) ?
The answer to inverse oflaplace 4/(s-2) is 4e^{2t}