What is area y=sqrt(x)+1,y=sqrt(2-x)+1,y=1 ?

The answer to area y=sqrt(x)+1,y=sqrt(2-x)+1,y=1 is 4/3

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area y=sqrt(x)+1,y=sqrt(2-x)+1,y=1

area

y = x + 1, y = 2 - x + 1, y = 1

\frac{4}{3}

Decimal Notation

1.33333 \dots

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x + 1 = 2 - x + 1 : x = 1

x + 1 = 1 : x = 0

2 - x + 1 = 1 : x = 2

= \int_{0}^{1} ∣ f_{1} (x) - f_{3} (x) ∣ d x + \int_{1}^{2} ∣ f_{3} (x) - f_{2} (x) ∣ d x

= \int_{0}^{1} x + 1 - 1 d x + \int_{1}^{2} 1 - (2 - x + 1) d x

\int_{0}^{1} x + 1 - 1 d x = \frac{2}{3}

\int_{1}^{2} 1 - (2 - x + 1) d x = \frac{2}{3}

= \frac{2}{3} + \frac{2}{3}

Simplify

= \frac{4}{3}

x^{2} y^{^{'}} + x y = 1, y (1) = 2

22 e^{x^{2}} x

n = 0 \sum \infty \frac{( 9 ^{n} )}{n !}

\int \frac{x + 3}{x ^{2} + 2 x + 2} d x

\int_{0}^{2} e^{x} d x

What is area y=sqrt(x)+1,y=sqrt(2-x)+1,y=1 ?
The answer to area y=sqrt(x)+1,y=sqrt(2-x)+1,y=1 is 4/3