What is the limit as x approaches 1 of (ln(x))/(x+1) ?

The limit as x approaches 1 of (ln(x))/(x+1) is 0

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limit as x approaches 1 of (ln(x))/(x+1)

x \to 1 lim (\frac{ln ( x )}{x + 1})

0

Solution steps

x \to 1 lim (\frac{ln ( x )}{x + 1})

Plug in the value

x = 1

= \frac{ln ( 1 )}{1 + 1}

Simplify

\frac{ln ( 1 )}{1 + 1} : 0

= 0

x \to π lim (\frac{- 2}{π - x})

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x \to \frac{π}{2} lim (2 cos (x))

What is the limit as x approaches 1 of (ln(x))/(x+1) ?
The limit as x approaches 1 of (ln(x))/(x+1) is 0