What is the derivative of f(x)=1+sin(x) ?

The derivative of f(x)=1+sin(x) is cos(x)

What is the first derivative of f(x)=1+sin(x) ?

The first derivative of f(x)=1+sin(x) is cos(x)

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derivative of

f (x) = 1 + sin (x)

cos (x)

Solution steps

\frac{d}{d x} (1 + sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (sin (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (sin (x)) = cos (x)

= 0 + cos (x)

Simplify

= cos (x)

\frac{d}{d x} (\frac{2 x}{x ^{2} + 2})

\frac{\partial}{\partial x} (\frac{1}{2})

x y^{^{'}} - y = - 2 x^{2} + x - 2

\frac{d}{d x} (\frac{csc ( x )}{x})

\int x^{3} e^{3} d x

What is the derivative of f(x)=1+sin(x) ?
The derivative of f(x)=1+sin(x) is cos(x)
What is the first derivative of f(x)=1+sin(x) ?
The first derivative of f(x)=1+sin(x) is cos(x)