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Popular >

xy^'-y=-2x^2+x-2

Solution

x y^{^{'}} - y = - 2 x^{2} + x - 2

Solution

y = - 2 x^{2} + x ln (x) + 2 + c_{1} x

Solution steps

x y^{'} (x) - y = - 2 x^{2} + x - 2

Solve linear ODE:

y = - 2 x^{2} + x ln (x) + 2 + c_{1} x

y = - 2 x^{2} + x ln (x) + 2 + c_{1} x

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Frequently Asked Questions (FAQ)

What is the solution for xy^'-y=-2x^2+x-2 ?
The solution for xy^'-y=-2x^2+x-2 is y=-2x^2+xln(x)+2+c_{1}x