What is the derivative of f(x)=x^2-sec(x)+1 ?

The derivative of f(x)=x^2-sec(x)+1 is 2x-sec(x)tan(x)

What is the first derivative of f(x)=x^2-sec(x)+1 ?

The first derivative of f(x)=x^2-sec(x)+1 is 2x-sec(x)tan(x)

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derivative of

f (x) = x^{2} - sec (x) + 1

2 x - sec (x) tan (x)

Solution steps

\frac{d}{d x} (x^{2} - sec (x) + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (sec (x)) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

\frac{d}{d x} (1) = 0

= 2 x - sec (x) tan (x) + 0

Simplify

= 2 x - sec (x) tan (x)

t cos (4 t)

f (x) = x^{3} - 3 x^{2} - 9 x + 5, at x = - 12

\int_{0}^{2} 0 d x

y^{^{'}} = (0.5 + sin (t)) (\frac{y}{5})

What is the derivative of f(x)=x^2-sec(x)+1 ?
The derivative of f(x)=x^2-sec(x)+1 is 2x-sec(x)tan(x)
What is the first derivative of f(x)=x^2-sec(x)+1 ?
The first derivative of f(x)=x^2-sec(x)+1 is 2x-sec(x)tan(x)