What is the limit as x approaches 3 of 3/(x^2-9) ?

The limit as x approaches 3 of 3/(x^2-9) is diverges

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limit as x approaches 3 of 3/(x^2-9)

x \to 3 lim (\frac{3}{x ^{2} - 9})

diverges

Solution steps

x \to 3 lim (\frac{3}{x ^{2} - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{3}{x ^{2} - 9}) = \infty

x \to 3 - lim (\frac{3}{x ^{2} - 9}) = - \infty

= diverges

x \to 5 lim (\frac{x - 5}{x - 25})

x \to \infty + lim (x n (x))

x \to - 0 lim (\frac{e ^{2} - 1}{x})

x \to \infty lim (\frac{4}{2})

x \to - \infty lim (3 x^{3} - 4)

What is the limit as x approaches 3 of 3/(x^2-9) ?
The limit as x approaches 3 of 3/(x^2-9) is diverges