What is the derivative of y=x^2+2x+6 ?

The derivative of y=x^2+2x+6 is 2x+2

What is the first derivative of y=x^2+2x+6 ?

The first derivative of y=x^2+2x+6 is 2x+2

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derivative of

y = x^{2} + 2 x + 6

2 x + 2

Solution steps

\frac{d}{d x} (x^{2} + 2 x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (6)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (6) = 0

= 2 x + 2 + 0

Simplify

= 2 x + 2

x^{2}, x + 2, 0

x \to 0 lim (\frac{e ^{x} - 1}{3 x})

f (x) = (4 x - 7)^{\frac{1}{2}}, at x = 4

\int e^{x} x^{2} d x

\frac{1}{e ^{y}} y^{^{'}} = \frac{1}{e ^{x}}

What is the derivative of y=x^2+2x+6 ?
The derivative of y=x^2+2x+6 is 2x+2
What is the first derivative of y=x^2+2x+6 ?
The first derivative of y=x^2+2x+6 is 2x+2