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Popular >

1/(e^y)y^'= 1/(e^x)

Solution

\frac{1}{e ^{y}} y^{^{'}} = \frac{1}{e ^{x}}

Solution

y = - ln (e^{- x} - c_{1})

Solution steps

\frac{1}{e ^{y}} y^{'} (x) = \frac{1}{e ^{x}}

Solve separable ODE:

y = - ln (e^{- x} - c_{1})

y = - ln (e^{- x} - c_{1})

Popular Examples

integral of (x^3-8)/(x-2)

\int \frac{x ^{3} - 8}{x - 2} d x

simplify 5/12 (3+sqrt(5))a^3 simplify

\frac{5}{12} (3 + 5) a^{3}

integral of x^2+y^5

\int x^{2} + y^{5} d y

derivative of (x^2-2e^x/(x+3e^x))

\frac{d}{d x} (\frac{x ^{2} - 2 e ^{x}}{x + 3 e ^{x}})

tangent of y=sqrt(7x+11),(2,5)tangent of

y = 7 x + 11, (2, 5)

Frequently Asked Questions (FAQ)

What is the solution for 1/(e^y)y^'= 1/(e^x) ?
The solution for 1/(e^y)y^'= 1/(e^x) is y=-ln(e^{-x}-c_{1})