What is the tangent of y=sqrt(7x+11),(2,5) ?

The tangent of y=sqrt(7x+11),(2,5) is y= 7/10 x+18/5

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tangent of y=sqrt(7x+11),(2,5)

tangent of

y = 7 x + 11, (2, 5)

y = \frac{7}{10} x + \frac{18}{5}

Solution steps

Find the slope of

y = 7 x + 11 : \frac{d y}{d x} = \frac{7}{2 7 x + 11}

Compute the slope of

y = 7 x + 11

(2, 5) : m = \frac{7}{10}

Find the line with slope m=

\frac{7}{10}

and passing through

(2, 5) : y = \frac{7}{10} x + \frac{18}{5}

y = \frac{7}{10} x + \frac{18}{5}

\frac{lo g _{6} ( x )}{e ^{4 x}}

f (t) = 8 t^{2} - t

4 x, at x = 4

3 x - 8 y x^{2} + 1 \frac{d y}{d x} = 0

y = x, at x = 1

What is the tangent of y=sqrt(7x+11),(2,5) ?
The tangent of y=sqrt(7x+11),(2,5) is y= 7/10 x+18/5