What is the tangent of 4sqrt(x),\at x=4 ?

The tangent of 4sqrt(x),\at x=4 is y=x+4

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tangent of 4sqrt(x),\at x=4

tangent of

4 x, at x = 4

y = x + 4

Solution steps

Find the tangent point:

(4, 8)

Find the slope of

y = 4 x : \frac{d y}{d x} = \frac{2}{x}

Compute the slope of

y = 4 x

x = 4 : m = 1

Find the line with slope m=

1

and passing through

(4, 8) : y = x + 4

y = x + 4

3 x - 8 y x^{2} + 1 \frac{d y}{d x} = 0

y = x, at x = 1

\int_{7}^{e^{5}} \frac{1}{x} d x

\frac{\partial}{\partial x} (sin (x \cdot y))

x \to 2 lim (2 x^{2} - 5 x - 3)

What is the tangent of 4sqrt(x),\at x=4 ?
The tangent of 4sqrt(x),\at x=4 is y=x+4