What is the integral from 7 to e^5 of 1/x ?

The integral from 7 to e^5 of 1/x is 5-ln(7)

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integral from 7 to e^5 of 1/x

\int_{7}^{e^{5}} \frac{1}{x} d x

5 - ln (7)

Decimal Notation

3.05408 \dots

Solution steps

\int_{7}^{e^{5}} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{7}^{e^{5}}

Compute the boundaries:

5 - ln (7)

= 5 - ln (7)

\frac{\partial}{\partial x} (sin (x \cdot y))

x \to 2 lim (2 x^{2} - 5 x - 3)

\frac{\partial ^{2}}{\partial x ^{2}} (ln (x^{2} + y^{2}))

\frac{d}{d x} ((3 x^{2} + 8)^{5})

\frac{1}{s} - \frac{s + 1}{s ^{2} + s + 10}

What is the integral from 7 to e^5 of 1/x ?
The integral from 7 to e^5 of 1/x is 5-ln(7)