What is the derivative of (3x^2+8^5) ?

The derivative of (3x^2+8^5) is 30x(3x^2+8)^4

What is the first derivative of (3x^2+8^5) ?

The first derivative of (3x^2+8^5) is 30x(3x^2+8)^4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((3 x^{2} + 8)^{5})

30 x (3 x^{2} + 8)^{4}

Solution steps

\frac{d}{d x} ((3 x^{2} + 8)^{5})

Apply the chain rule:

5 (3 x^{2} + 8)^{4} \frac{d}{d x} (3 x^{2} + 8)

= 5 (3 x^{2} + 8)^{4} \frac{d}{d x} (3 x^{2} + 8)

\frac{d}{d x} (3 x^{2} + 8) = 6 x

= 5 (3 x^{2} + 8)^{4} \cdot 6 x

Simplify

= 30 x (3 x^{2} + 8)^{4}

\frac{1}{s} - \frac{s + 1}{s ^{2} + s + 10}

x \to \infty lim (- 1^{+})

x^{3} + 9 x - 5 π

\int e^{4 - 3 x} d x

x \to - 3 lim (\frac{1}{x + 3})

What is the derivative of (3x^2+8^5) ?
The derivative of (3x^2+8^5) is 30x(3x^2+8)^4
What is the first derivative of (3x^2+8^5) ?
The first derivative of (3x^2+8^5) is 30x(3x^2+8)^4