What is the limit as x approaches 5 of (x^2)/(2x-3) ?

The limit as x approaches 5 of (x^2)/(2x-3) is 25/7

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limit as x approaches 5 of (x^2)/(2x-3)

x \to 5 lim (\frac{x ^{2}}{2 x - 3})

\frac{25}{7}

Decimal

3.57142 \dots

Solution steps

x \to 5 lim (\frac{x ^{2}}{2 x - 3})

Plug in the value

x = 5

= \frac{5 ^{2}}{2 \cdot 5 - 3}

Simplify

= \frac{25}{7}

x \to 1 lim (\frac{2 x - 3}{3 x})

x \to 3 - lim (∣ 4 x ∣ - 3 x)

x \to 3 lim ([x] + [4 - x])

x \to (0) lim (\frac{3 x y}{5 x ^{2} + 2 y ^{2}})

x \to 3 lim ((x^{2}) (x + 3))

What is the limit as x approaches 5 of (x^2)/(2x-3) ?
The limit as x approaches 5 of (x^2)/(2x-3) is 25/7