What is the derivative of x^3+9x-5pi ?

The derivative of x^3+9x-5pi is 3x^2+9

What is the first derivative of x^3+9x-5pi ?

The first derivative of x^3+9x-5pi is 3x^2+9

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derivative of

x^{3} + 9 x - 5 π

3 x^{2} + 9

Solution steps

\frac{d}{d x} (x^{3} + 9 x - 5 π)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (9 x) - \frac{d}{d x} (5 π)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (5 π) = 0

= 3 x^{2} + 9 - 0

Simplify

= 3 x^{2} + 9

\int e^{4 - 3 x} d x

x \to - 3 lim (\frac{1}{x + 3})

\frac{s + 3}{( s + 1 ) ( s + 2 )}

\frac{\partial}{\partial x} (- y cos (x))

y^{^{''}} + 4 y^{^{'}} + 3 y = 4 e^{- x}

What is the derivative of x^3+9x-5pi ?
The derivative of x^3+9x-5pi is 3x^2+9
What is the first derivative of x^3+9x-5pi ?
The first derivative of x^3+9x-5pi is 3x^2+9