What is (\partial)/(\partial x)(-ycos(x)) ?

The answer to (\partial)/(\partial x)(-ycos(x)) is ysin(x)

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(\partial)/(\partial x)(-ycos(x))

\frac{\partial}{\partial x} (- y cos (x))

y sin (x)

Solution steps

\frac{\partial}{\partial x} (- y cos (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - y \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= - y (- sin (x))

Simplify

= y sin (x)

y^{^{''}} + 4 y^{^{'}} + 3 y = 4 e^{- x}

\frac{\partial}{\partial x} (x \cdot sin (x + y))

\int (1 - sin (x)) d x

y = 6 tan (x), at x = \frac{π}{3}

\frac{d}{d x} (\frac{tan ( \frac{x}{2} ) - 3}{3})

What is (\partial)/(\partial x)(-ycos(x)) ?
The answer to (\partial)/(\partial x)(-ycos(x)) is ysin(x)