What is the tangent of y=6tan(x),\at x= pi/3 ?

The tangent of y=6tan(x),\at x= pi/3 is y=24x+6sqrt(3)-8pi

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tangent of y=6tan(x),\at x= pi/3

tangent of

y = 6 tan (x), at x = \frac{π}{3}

y = 24 x + 63 - 8 π

Solution steps

Find the tangent point:

(\frac{π}{3}, 63)

Find the slope of

y = 6 tan (x) : \frac{d y}{d x} = 6 sec^{2} (x)

Compute the slope of

y = 6 tan (x)

x = \frac{π}{3} : m = 24

Find the line with slope m=

24

and passing through

(\frac{π}{3}, 63) : y = 24 x + 63 - 8 π

y = 24 x + 63 - 8 π

\frac{d}{d x} (\frac{tan ( \frac{x}{2} ) - 3}{3})

y = es (s^{3} + 10), (0, 10)

\int \frac{7 ln ( x + 9 )}{x ^{2}} d x

x \to \infty lim (1 + e^{x})

x \to 2 lim (\frac{( x - 2 )}{( x - 1 - 3 - x )})

What is the tangent of y=6tan(x),\at x= pi/3 ?
The tangent of y=6tan(x),\at x= pi/3 is y=24x+6sqrt(3)-8pi