What is the tangent of f(x)=-3x^{3/2}-1,\at x=4 ?

The tangent of f(x)=-3x^{3/2}-1,\at x=4 is y=-9x+11

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tangent of f(x)=-3x^{3/2}-1,\at x=4

tangent of

f (x) = - 3 x^{\frac{3}{2}} - 1, at x = 4

y = - 9 x + 11

Solution steps

Find the tangent point:

(4, - 25)

Find the slope of

f (x) = - 3 x^{\frac{3}{2}} - 1 : \frac{df ( x )}{d x} = - \frac{9 x ^{\frac{1}{2}}}{2}

Compute the slope of

f (x) = - 3 x^{\frac{3}{2}} - 1

x = 4 : m = - 9

Find the line with slope m=

- 9

and passing through

(4, - 25) : y = - 9 x + 11

y = - 9 x + 11

f (x) = e^{1 - 2 x} (x + cos (2 x))

f (x) = x^{3} + x^{2} + 1, g (x) = 2 x + 1

\int \frac{1}{25 - 36 x ^{2}} d x

n = 4 \sum \infty e^{5 - 6 n}

\frac{\partial}{\partial y} (y (1 + ln (x y)))

What is the tangent of f(x)=-3x^{3/2}-1,\at x=4 ?
The tangent of f(x)=-3x^{3/2}-1,\at x=4 is y=-9x+11