What is the integral from 1 to 6 of ln(x) ?

The integral from 1 to 6 of ln(x) is 6ln(6)-5

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integral from 1 to 6 of ln(x)

\int_{1}^{6} ln (x) d x

6 ln (6) - 5

Decimal Notation

5.75055 \dots

Solution steps

\int_{1}^{6} ln (x) d x

Apply Integration By Parts

: [x ln (x) - \int 1 d x]_{1}^{6}

= [x ln (x) - \int 1 d x]_{1}^{6}

\int 1 d x = x

= [x ln (x) - x]_{1}^{6}

Compute the boundaries:

6 ln (6) - 5

= 6 ln (6) - 5

\frac{d}{d t} (e^{a (e^{t} - 1)})

y^{^{''}} + 3 y^{^{'}} + 2 y = 7 cos (x) - sin (x)

\frac{\partial}{\partial z} (- z^{2})

\int \frac{6 x + 5}{( 9 x ^{2} + 15 x ) ^{5}} d x

What is the integral from 1 to 6 of ln(x) ?
The integral from 1 to 6 of ln(x) is 6ln(6)-5