What is (\partial)/(\partial z)(-z^2) ?

The answer to (\partial)/(\partial z)(-z^2) is -2z

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(\partial)/(\partial z)(-z^2)

\frac{\partial}{\partial z} (- z^{2})

- 2 z

Solution steps

\frac{\partial}{\partial z} (- z^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial z} (z^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 z^{2 - 1}

Simplify

= - 2 z

\int \frac{6 x + 5}{( 9 x ^{2} + 15 x ) ^{5}} d x

\int_{4}^{8} t^{3} ln (5 t) d t

x y^{^{'}} + 2 y = 2 cos (x)

\frac{x ^{2} - 9 x + 1}{x ^{2} + 5}

5 sin^{2} (t)

What is (\partial)/(\partial z)(-z^2) ?
The answer to (\partial)/(\partial z)(-z^2) is -2z