What is the derivative of y=(3x-2x^2)^3 ?

The derivative of y=(3x-2x^2)^3 is 3(3x-2x^2)^2(3-4x)

What is the first derivative of y=(3x-2x^2)^3 ?

The first derivative of y=(3x-2x^2)^3 is 3(3x-2x^2)^2(3-4x)

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derivative of

y = (3 x - 2 x^{2})^{3}

3 (3 x - 2 x^{2})^{2} (3 - 4 x)

Solution steps

\frac{d}{d x} ((3 x - 2 x^{2})^{3})

Apply the chain rule:

3 (3 x - 2 x^{2})^{2} \frac{d}{d x} (3 x - 2 x^{2})

= 3 (3 x - 2 x^{2})^{2} \frac{d}{d x} (3 x - 2 x^{2})

\frac{d}{d x} (3 x - 2 x^{2}) = 3 - 4 x

= 3 (3 x - 2 x^{2})^{2} (3 - 4 x)

\frac{9 + 6 x}{7 - 4 x}

y = e^{x} (p + p p)

ln (2 - 3 x)

\frac{d y}{d x} = \frac{x sec ( \frac{y}{x} ) + y}{x}

\int sec (\frac{x}{2}) tan (\frac{x}{2}) d x

What is the derivative of y=(3x-2x^2)^3 ?
The derivative of y=(3x-2x^2)^3 is 3(3x-2x^2)^2(3-4x)
What is the first derivative of y=(3x-2x^2)^3 ?
The first derivative of y=(3x-2x^2)^3 is 3(3x-2x^2)^2(3-4x)