What is (\partial)/(\partial z)(z^2cos(yx)) ?

The answer to (\partial)/(\partial z)(z^2cos(yx)) is 2zcos(yx)

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(\partial)/(\partial z)(z^2cos(yx))

\frac{\partial}{\partial z} (z^{2} cos (y x))

2 z cos (y x)

Solution steps

\frac{\partial}{\partial z} (z^{2} cos (y x))

Treat

y, x

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (y x) \frac{\partial}{\partial z} (z^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= cos (y x) \cdot 2 z^{2 - 1}

Simplify

= 2 z cos (y x)

f (x) = (4 t - 1) (3 t - 6)^{- 1}

\int \frac{x ^{2}}{( x ^{3} - 6 ) ^{2}} d x

f (x) = \frac{1}{x ^{10}}

f (x) = x + 7, (9, 4)

\frac{d x}{d t} = \frac{2 x ^{2} + t 7 t ^{2} + x ^{2}}{2 t x}

What is (\partial)/(\partial z)(z^2cos(yx)) ?
The answer to (\partial)/(\partial z)(z^2cos(yx)) is 2zcos(yx)