What is the sum from n=0 to infinity of ln(1-n) ?

The sum from n=0 to infinity of ln(1-n) is diverges

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sum from n=0 to infinity of ln(1-n)

n = 0 \sum \infty ln (1 - n)

diverges

Solution steps

n = 2 \sum \infty ln (1 - n)

Apply Series Divergence Test:

diverges

= diverges

k = 0 \sum \infty \frac{k}{k + 1}

n = 1 \sum \infty 2^{n} - n

n = 0 \sum \infty \frac{n}{n + 5}

n = 1 \sum \infty \frac{8}{n}

n = 1 \sum \infty \frac{1}{n ^{\frac{1}{5}}}

What is the sum from n=0 to infinity of ln(1-n) ?
The sum from n=0 to infinity of ln(1-n) is diverges