What is the sum from n=1 to infinity of arccos(1/n) ?

The sum from n=1 to infinity of arccos(1/n) is diverges

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sum from n=1 to infinity of arccos(1/n)

n = 1 \sum \infty arccos (\frac{1}{n})

diverges

Solution steps

n = 1 \sum \infty arccos (\frac{1}{n})

Apply Series Divergence Test:

diverges

= diverges

n = 2 \sum \infty \frac{n}{3 ^{n}}

n = 2 \sum \infty (\frac{1}{3})^{2 n}

n = 0 \sum \infty \frac{1}{n ^{e}}

n = 1 \sum \infty \frac{1}{n ^{2} + 2 n - 3}

n = 1 \sum \infty \frac{1}{n ^{0.6}}

What is the sum from n=1 to infinity of arccos(1/n) ?
The sum from n=1 to infinity of arccos(1/n) is diverges