What is the sum from n=1 to infinity of 1/(n^5+2) ?

The sum from n=1 to infinity of 1/(n^5+2) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of 1/(n^5+2)

n = 1 \sum \infty \frac{1}{n ^{5} + 2}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{5} + 2}

Apply Series Comparison Test:

converges

= converges

n = 1 \sum \infty \frac{1}{1 + 0. 5 ^{n}}

n = 0 \sum \infty \frac{1}{1 - 2 n}

n = 0 \sum \infty \frac{3}{n ^{2} + 3 n + 2}

n = 1 \sum \infty 4 (\frac{1}{3})^{n - 1}

n = 1 \sum \infty 3 n^{2} e^{- n^{3}}

What is the sum from n=1 to infinity of 1/(n^5+2) ?
The sum from n=1 to infinity of 1/(n^5+2) is converges