What is the sum from n=0 to infinity of (-3/8)^n ?

The sum from n=0 to infinity of (-3/8)^n is 8/11

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sum from n=0 to infinity of (-3/8)^n

n = 0 \sum \infty (- \frac{3}{8})^{n}

\frac{8}{11}

Solution steps

n = 0 \sum \infty (- \frac{3}{8})^{n}

Apply Series Geometric Test:

\frac{8}{11}

= \frac{8}{11}

n = 0 \sum \infty \frac{n + 1}{n + 2}

n = 3 \sum \infty \frac{sin ( nπ )}{n}

n = 1 \sum \infty 4^{- 3 n}

k = 0 \sum \infty e^{- k}

n = 0 \sum \infty \frac{3}{5 - n}

What is the sum from n=0 to infinity of (-3/8)^n ?
The sum from n=0 to infinity of (-3/8)^n is 8/11