What is the derivative of 6t^2-4t+9 ?

The derivative of 6t^2-4t+9 is 12t-4

What is the first derivative of 6t^2-4t+9 ?

The first derivative of 6t^2-4t+9 is 12t-4

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derivative of

6 t^{2} - 4 t + 9

12 t - 4

Solution steps

\frac{d}{d t} (6 t^{2} - 4 t + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (6 t^{2}) - \frac{d}{d t} (4 t) + \frac{d}{d t} (9)

\frac{d}{d t} (6 t^{2}) = 12 t

\frac{d}{d t} (4 t) = 4

\frac{d}{d t} (9) = 0

= 12 t - 4 + 0

Simplify

= 12 t - 4

f (t) = 2 e^{- t} cos (4 t)

\int \frac{cos ( 2 x )}{( 1 + sin ( 2 x ) ) ^{2}} d x

\frac{d}{d x} (12 x - x^{2})

\int 6 sin^{5} (x) cos (x) d x

\frac{d}{d x} (\frac{3}{4} x^{\frac{4}{3}} - \frac{3}{8} x^{\frac{2}{3}} + 8)

What is the derivative of 6t^2-4t+9 ?
The derivative of 6t^2-4t+9 is 12t-4
What is the first derivative of 6t^2-4t+9 ?
The first derivative of 6t^2-4t+9 is 12t-4