What is the derivative of 3/4 x^{4/3}-3/8 x^{2/3}+8 ?

The derivative of 3/4 x^{4/3}-3/8 x^{2/3}+8 is (-1+4x^{2/3})/(4x^{1/3)}

What is the first derivative of 3/4 x^{4/3}-3/8 x^{2/3}+8 ?

The first derivative of 3/4 x^{4/3}-3/8 x^{2/3}+8 is (-1+4x^{2/3})/(4x^{1/3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{3}{4} x^{\frac{4}{3}} - \frac{3}{8} x^{\frac{2}{3}} + 8)

\frac{- 1 + 4 x ^{\frac{2}{3}}}{4 x ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} (\frac{3}{4} x^{\frac{4}{3}} - \frac{3}{8} x^{\frac{2}{3}} + 8)

Simplify

\frac{3}{4} x^{\frac{4}{3}} - \frac{3}{8} x^{\frac{2}{3}} + 8 : \frac{3 x ^{\frac{4}{3}}}{4} - \frac{3 x ^{\frac{2}{3}}}{8} + 8

= \frac{d}{d x} (\frac{3 x ^{\frac{4}{3}}}{4} - \frac{3 x ^{\frac{2}{3}}}{8} + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{3 x ^{\frac{4}{3}}}{4}) - \frac{d}{d x} (\frac{3 x ^{\frac{2}{3}}}{8}) + \frac{d}{d x} (8)

\frac{d}{d x} (\frac{3 x ^{\frac{4}{3}}}{4}) = x^{\frac{1}{3}}

\frac{d}{d x} (\frac{3 x ^{\frac{2}{3}}}{8}) = \frac{1}{4 x ^{\frac{1}{3}}}

\frac{d}{d x} (8) = 0

= x^{\frac{1}{3}} - \frac{1}{4 x ^{\frac{1}{3}}} + 0

Simplify

x^{\frac{1}{3}} - \frac{1}{4 x ^{\frac{1}{3}}} + 0 : \frac{- 1 + 4 x ^{\frac{2}{3}}}{4 x ^{\frac{1}{3}}}

= \frac{- 1 + 4 x ^{\frac{2}{3}}}{4 x ^{\frac{1}{3}}}

\frac{d}{d x} (x^{4} - 3 x^{2} + 4)

\int x (x - 1) (x - 2) d x

y = (2 x^{2} - 3)^{2}

\int_{1}^{9} 4 x d x

\int \frac{1}{tan ( x ) + sin ( x )} d x

What is the derivative of 3/4 x^{4/3}-3/8 x^{2/3}+8 ?
The derivative of 3/4 x^{4/3}-3/8 x^{2/3}+8 is (-1+4x^{2/3})/(4x^{1/3)}
What is the first derivative of 3/4 x^{4/3}-3/8 x^{2/3}+8 ?
The first derivative of 3/4 x^{4/3}-3/8 x^{2/3}+8 is (-1+4x^{2/3})/(4x^{1/3)}