What is the sum from n=1 to infinity of 1/(n^{0.2)} ?

The sum from n=1 to infinity of 1/(n^{0.2)} is diverges

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sum from n=1 to infinity of 1/(n^{0.2)}

n = 1 \sum \infty \frac{1}{n ^{0.2}}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{0.2}}

Apply p-Series Test:

diverges

= diverges

n = 1 \sum \infty (0.9)^{n - 1}

k = 2 \sum \infty \frac{1}{k}

n = 2 \sum \infty n sin (\frac{10}{n})

n = 1 \sum \infty (\frac{3}{π})^{n}

n = 1 \sum \infty n \cdot (\frac{1}{2})^{n}

What is the sum from n=1 to infinity of 1/(n^{0.2)} ?
The sum from n=1 to infinity of 1/(n^{0.2)} is diverges