What is the sum from n=1 to infinity of (e^n)/(n^6) ?

The sum from n=1 to infinity of (e^n)/(n^6) is diverges

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sum from n=1 to infinity of (e^n)/(n^6)

n = 1 \sum \infty \frac{e ^{n}}{n ^{6}}

diverges

Solution steps

n = 1 \sum \infty \frac{e ^{n}}{n ^{6}}

Apply Series Ratio Test:

diverges

= diverges

n = 0 \sum \infty \frac{2 ^{n}}{n}

i = 1 \sum \infty 2 (\frac{4}{i})^{3} + 9

n = 1 \sum \infty \frac{1}{n} (\frac{4}{5})^{n}

n = 1 \sum \infty cos (\frac{9}{n})

n = 3 \sum \infty ln (1 + \frac{1}{n})

What is the sum from n=1 to infinity of (e^n)/(n^6) ?
The sum from n=1 to infinity of (e^n)/(n^6) is diverges