What is the derivative of f(x)=2e^{-3x+9} ?

The derivative of f(x)=2e^{-3x+9} is -6e^{-3x+9}

What is the first derivative of f(x)=2e^{-3x+9} ?

The first derivative of f(x)=2e^{-3x+9} is -6e^{-3x+9}

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derivative of

f (x) = 2 e^{- 3 x + 9}

- 6 e^{- 3 x + 9}

Solution steps

\frac{d}{d x} (2 e^{- 3 x + 9})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{- 3 x + 9})

Apply the chain rule:

e^{- 3 x + 9} \frac{d}{d x} (- 3 x + 9)

= e^{- 3 x + 9} \frac{d}{d x} (- 3 x + 9)

\frac{d}{d x} (- 3 x + 9) = - 3

= 2 e^{- 3 x + 9} (- 3)

Simplify

= - 6 e^{- 3 x + 9}

(- 2, - 1), (8, - 3)

\int \frac{sec ( x )}{tan ( x ) + cot ( x )} d x

\int 4 x - 2 x^{2} d x

\int a^{(3 x + 3)} d x

y^{'} = y (3 - y) - \frac{9}{4}

What is the derivative of f(x)=2e^{-3x+9} ?
The derivative of f(x)=2e^{-3x+9} is -6e^{-3x+9}
What is the first derivative of f(x)=2e^{-3x+9} ?
The first derivative of f(x)=2e^{-3x+9} is -6e^{-3x+9}