What is the sum from n=3 to infinity of 1/(n^3) ?

The sum from n=3 to infinity of 1/(n^3) is converges

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sum from n=3 to infinity of 1/(n^3)

n = 3 \sum \infty \frac{1}{n ^{3}}

converges

Solution steps

n = 3 \sum \infty \frac{1}{n ^{3}}

Apply p-Series Test:

converges

= converges

n = 1 \sum \infty \frac{n}{2 ^{n} ( n + 1 )}

n = 2 \sum \infty \frac{e ^{n}}{π ^{n}}

n = 0 \sum \infty 2^{- n}

n = 0 \sum \infty (0.3)^{n}

n = 0 \sum \infty (1 + \frac{2}{5 n})^{n}

What is the sum from n=3 to infinity of 1/(n^3) ?
The sum from n=3 to infinity of 1/(n^3) is converges