What is the limit as x approaches 0+of x^{4x} ?

The limit as x approaches 0+of x^{4x} is 1

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limit as x approaches 0+of x^{4x}

x \to 0 + lim (x^{4 x})

1

Solution steps

x \to 0 + lim (x^{4 x})

Apply exponent rules

= x \to 0 + lim (e^{4 x l n (x)})

Apply the Limit Chain Rule:

1

= 1

\frac{d y}{d x} = \frac{1}{5} x

f (x) = x^{2} - 4, at x = 3

\int e^{4 θ} sin (5 θ) d θ

f (x) = 3 x^{2}, g (x) = - 3 x + 6, [- 4, 2]

4 e^{x} - 3 x^{2}

What is the limit as x approaches 0+of x^{4x} ?
The limit as x approaches 0+of x^{4x} is 1