What is the sum from n=1 to infinity of (n+1)/(2n-1) ?

The sum from n=1 to infinity of (n+1)/(2n-1) is diverges

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sum from n=1 to infinity of (n+1)/(2n-1)

n = 1 \sum \infty \frac{n + 1}{2 n - 1}

diverges

Solution steps

n = 1 \sum \infty \frac{n + 1}{2 n - 1}

Apply Series Divergence Test:

diverges

= diverges

n = 0 \sum \infty (- 1)^{n - 1}

n = 1 \sum \infty (9.9)^{n}

n = 1 \sum \infty 7 (0.8)^{n - 1}

n = 1 \sum \infty \frac{n}{13 n + 4}

n = 0 \sum \infty \frac{4}{5 - n}

What is the sum from n=1 to infinity of (n+1)/(2n-1) ?
The sum from n=1 to infinity of (n+1)/(2n-1) is diverges