What is the sum from n=2 to infinity of (5/6)^{2n} ?

The sum from n=2 to infinity of (5/6)^{2n} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=2 to infinity of (5/6)^{2n}

n = 2 \sum \infty (\frac{5}{6})^{2 n}

converges

Solution steps

n = 2 \sum \infty (\frac{5}{6})^{2 n}

Apply Series Ratio Test:

converges

= converges

k = 5 \sum \infty \frac{1}{k ^{2} - k}

n = 0 \sum \infty (2)^{n}

n = 1 \sum \infty \frac{3 ^{n}}{n + 1}

k = 1 \sum \infty ln (\frac{k}{3 k + 1})

n = 0 \sum \infty \frac{n}{8 n + 1}

What is the sum from n=2 to infinity of (5/6)^{2n} ?
The sum from n=2 to infinity of (5/6)^{2n} is converges