What is the sum from n=0 to infinity}(\sqrt{2 of)^n ?

The sum from n=0 to infinity}(\sqrt{2 of)^n is diverges

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sum from n=0 to infinity}(\sqrt{2 of)^n

n = 0 \sum \infty (2)^{n}

diverges

Solution steps

n = 0 \sum \infty (2)^{n}

Apply Series Geometric Test:

diverges

= diverges

n = 1 \sum \infty \frac{3 ^{n}}{n + 1}

k = 1 \sum \infty ln (\frac{k}{3 k + 1})

n = 0 \sum \infty \frac{n}{8 n + 1}

n = 0 \sum \infty sin (\frac{n}{2})

n = 0 \sum \infty \frac{1}{1 - 3 n}

What is the sum from n=0 to infinity}(\sqrt{2 of)^n ?
The sum from n=0 to infinity}(\sqrt{2 of)^n is diverges