What is the derivative of 2csc(1-3x) ?

The derivative of 2csc(1-3x) is 6cot(1-3x)csc(1-3x)

What is the first derivative of 2csc(1-3x) ?

The first derivative of 2csc(1-3x) is 6cot(1-3x)csc(1-3x)

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derivative of

2 csc (1 - 3 x)

6 cot (1 - 3 x) csc (1 - 3 x)

Solution steps

\frac{d}{d x} (2 csc (1 - 3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (csc (1 - 3 x))

Apply the chain rule:

- cot (1 - 3 x) csc (1 - 3 x) \frac{d}{d x} (1 - 3 x)

= - cot (1 - 3 x) csc (1 - 3 x) \frac{d}{d x} (1 - 3 x)

\frac{d}{d x} (1 - 3 x) = - 3

= 2 (- cot (1 - 3 x) csc (1 - 3 x) (- 3))

Simplify

= 6 cot (1 - 3 x) csc (1 - 3 x)

f (x) = (2 x + 3)^{5}, at x = - 1

\frac{d y}{d x} - 2 y = 0

y^{^{''}} + 4 y^{^{'}} + 3 y = 3 x + 7

\int sin^{3} (x co) s^{7} x d x

What is the derivative of 2csc(1-3x) ?
The derivative of 2csc(1-3x) is 6cot(1-3x)csc(1-3x)
What is the first derivative of 2csc(1-3x) ?
The first derivative of 2csc(1-3x) is 6cot(1-3x)csc(1-3x)