What is the sum from n=1 to infinity of (10^n)/(n+1) ?

The sum from n=1 to infinity of (10^n)/(n+1) is diverges

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sum from n=1 to infinity of (10^n)/(n+1)

n = 1 \sum \infty \frac{1 0 ^{n}}{n + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{1 0 ^{n}}{n + 1}

Apply Series Ratio Test:

diverges

= diverges

n = 1 \sum \infty tan (\frac{3}{k ^{2}})

n = 0 \sum \infty \frac{n}{3 n + 2}

n = 0 \sum \infty \frac{4}{7 - n}

n = 1 \sum \infty \frac{7 ^{n}}{n + 1}

n = 0 \sum \infty 2^{n} - n

What is the sum from n=1 to infinity of (10^n)/(n+1) ?
The sum from n=1 to infinity of (10^n)/(n+1) is diverges